# Neon number program in java

## Neon number program in java

Write a program in java to accept a number from the user and check if it is a neon number or not.

The neon number is nothing but the sum of digits of square of the number is equal to the number.
Example :
Input number 9
Square the number 9 * 9 and it comes to 81
Sum the digits of the square number 8 + 1 = 9
If the number is equal to the sum of the square number then it is a neon the number and if it is not then it is not a neon number.

### Java program of Neon Number Example

import java.util.*;
// Neon Number Class
public class NeonNumberCheck
{
// main method begins execution of this class
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
int n;      // n for number to check neon or not
int m;      // m for square of the n
int a;      // a for taking reminder
int s=0;    // for summation
System.out.println("Enter a number: ");
n=sc.nextInt();
m=n*n;      // Squaring of the number n
while(m!=0)
{
a=m%10; // Calculating reminder
s=s+a;  // adding the reminder to s
m=m/10; // Integer division to truncate the last digit
}
if(s == n)  // Checking the original number to the summation
{
System.out.println("Neon number");
}
else
{
System.out.println("Not a Neon Number");
}
}
}

Sample output
Enter a number:
8
Not a Neon Number
Enter a number:
9
Neon number
Enter a number:
10
Not a Neon Number

In the above program, the entered number is calculated as m = n*n and then 'm' is mode division by 10 and reminder added to s as s=s+a and then integer division is don till number become Zero.
After check it as
if(s == n)  // Checking the original number to the summation
{
System.out.println("Neon number");
}
else
{
System.out.println("Not a Neon Number");
}
This will give the required result.

Variable Description
 Sr. No Variable / Function Types Description 1 sc Object Object of Scanner class 2 main() void main() method 3 n int No to be check as NEON no. 4 m int Store n 5 a int For reminder 6 s int Summation calculation

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