Menu-driven program in java using switch case
Write a java program to print series 0, 3, 8, 15, 24, and s=1/2+3/4+5/6+..+19/20 with help of Menu using a switch case statement.
Solution:import java.io.*;
public class MenuSeries
{
public static void main(String args[])throws IOException
{
InputStreamReader in=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(in);
char choice;
int n,i;
double s=0;
System.out.print("Enter n number:");
n=Integer.parseInt(br.readLine());
System.out.println("A or a for series 0,3,8,15,24……");
System.out.println("B or b fro series s=1/2+3/4+5/6+..+19/20");
System.out.println("Enter your choice:");
choice=(char)br.read();
switch(choice)
{
case 'A':
case 'a':
for(i=1;i<=n;i++)
{
System.out.print((i*i)-1+",");
}
break;
case 'B':
case 'b':
for(i=2;i<=20;i+=2)
{
s=s+(double)(i-1)/i;
}
System.out.println("Sum="+s);
break;
default:
System.out.print("Wrong choice.....");
}
}
}
Java Menu driven program to find Composite number and Smallest digit search
import java.io.*;public class Menu
{
public static void main(String args[])throws IOException
{
InputStreamReader in=new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(in);
int n, count, ch, small, a, i;
System.out.println("Enter 1 for Composite number");
System.out.println("Enter 2 for Smallest digit search");
System.out.print("Enter your choice :");
ch=Integer.parseInt(br.readLine());
switch(ch)
{
case 1:
count=0;
System.out.print("Enter a number :");
n= Integer.parseInt(br.readLine());
for(i=2; i<=n/2; i++)
{
if(n % i == 0)
count++;
}
if(count>0)
System.out.println("Entered number is Composite number");
else
System.out.println("Entered number is not Composite number");
break;
case 2:
System.out.print("Enter a number :");
n= Integer.parseInt(br.readLine());
small=99;
while(n!=0)
{
a = n % 10;
if(a < small)
{
small = a;
}
n = n / 10;
}
System.out.println("Smallest number is " + small);
break;
default:
System.out.println("Wrong choice");
}
}
}
MENU DRIVEN PROGRAM IN JAVA SIMPLE CALCULATOR
import java.io.*;
public class Menu
{
private int a; //Instance Variable
private int b;
private int c;
private static InputStreamReader in=new
InputStreamReader(System.in);
private static BufferedReader br=new
BufferedReader(in);
void menu()
{
//System.out.println("\f");
System.out.println("1.
Addition");
System.out.println("2.
Subtraction");
System.out.println("3.
Multiplication");
System.out.println("4.
Division");
System.out.println("5.
Exit");
System.out.println("Press your
choice.........>");
}
void sum (int a, int b)
{
this.a=a;
this.b=b;
this.c=this.a+this.b;
System.out.println("Sum="+this.c);
// this.a=Integer.parseInt(br.readLine());
}
void sub (int x, int y)
{
a=x;
b=y;
c=a-b;
System.out.println("Subtraction="+c);
}
void mult (int x, int y)
{
a=x;
b=y;
c=a*b;
System.out.println("Multplication="+c);
}
void div (int x, int y)
{
a=x;
b=y;
c=a/b;
System.out.println("Division="+c);
}
public static void main(String
args[])throws IOException
{
Menu ob=new Menu();
int ch,a,b;
ch=0;
do
{
ob.menu();
ch=Integer.parseInt(br.readLine());
switch(ch)
{
case 1:
System.out.println("Enter
two number");
a= Integer.parseInt(br.readLine());
b= Integer.parseInt(br.readLine());
ob.sum(a, b);
break;
case 2:
System.out.println("Enter
two number");
a=Integer.parseInt(br.readLine());
b=Integer.parseInt(br.readLine());
ob.sub(a, b);
break;
case 3:
System.out.println("Enter
two number");
a=Integer.parseInt(br.readLine());
b=Integer.parseInt(br.readLine());
ob.mult(a, b);
break;
case 4:
System.out.println("Enter
two number");
a=Integer.parseInt(br.readLine());
b=Integer.parseInt(br.readLine());
ob.div(a, b);
break;
case 5:
System.exit(0);
default:
System.out.println("Wrong
choice:");
}
}while(ch!=5);
}
}
Sample Output
1. Addition
2. Subtraction
3. Multiplication
4. Division
5. Exit
Press your
choice.........>
1
Enter two number
2
5
Sum=7
1. Addition
2. Subtraction
3. Multiplication
4. Division
5. Exit
Press your
choice.........>
5
1.
S=1/4+1/8+1/12………upto n terms
Write a menu driven program to find the sum of the following series depending on the user choosing 1 or 2
1.
S=1/4+1/8+1/12………upto n terms
2.
S=1/1! - 2/2! + 3/3!…….upto n terms
Where
! Stands for factorial of the number and the factorial value of a number is the
product of all integers from 1 to that number, e.g. 5! = 1 × 2 × 3 × 4 × 5. (use switch-case).
import
java.util.*;
public
class SeriesClass
{
double s;
int f, i, j , t, n;
SeriesClass() // Constructor
{
s=0.0;
}
double series1(int no)
{
t=4;
n=no;
for(i=0; i<n; i++)
{
s = s + (double)1/t; // 1/4, 1/8,
1/12......
t=t+4;
}
return s;
}
double series2(int no)
{
n=no;
for(i=1; i<=n; i++)
{
f=1;
//for factorial
for(j=1;j<=i; j++)
{
f=f*j;
} // end of factorial
if(i%2==0)
{
s = s - (double)i/f;
}
else
{
s = s + (double)i/f;
}
}
return s;
}
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
SeriesClass ob=new SeriesClass();
int ch, num;
double sum;
System.out.println("1 for
S=1/4+1/8+1/12………upto n terms");
System.out.println("2 for S=1/1! -
2/2! + 3/3!…….upto n terms");
System.out.println("Enter your
choice---->");
ch=sc.nextInt();
switch(ch)
{
case 1:
System.out.println("Enter n
terms:");
num=sc.nextInt();
sum=ob.series1(num);
System.out.println("Sum="+sum);
break;
case 2:
System.out.println("Enter n
terms:");
num=sc.nextInt();
sum=ob.series2(num);
System.out.println("Sum="+sum);
break;
default:
System.out.println("Wrong
Choice...");
}
}
}
Variable/Method
Description or Documentation
Sr. No
|
Variable / Method
|
Type
|
Description
|
1
|
s
|
double
|
d is
assign for Summation
|
2
|
I, j
|
int
|
i and
j are use for Loop
|
3
|
t
|
int
|
For increment
4
|
4
|
n
|
int
|
N is
use to assign the number
|
5
|
SeriesClass()
|
It is
a constructor
|
|
6
|
series1(int
no)
|
double
|
For the
first series
|
7
|
Series2(int
no)
|
double
|
For the
second series
|
8
|
main()
|
void
|
This
is a main method from where java program will run
|
9
|
sc
|
object
|
Object
of Scanner class
|
10
|
ob
|
Object
|
Object
of Class SeriesClass
|
11
|
ch
|
int
|
It is
used for choice
|
12
|
num
|
int
|
For number
|
13
|
sum
|
double
|
For summation
|
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